4x^2+60x-551=0

Solution for 4x^2+60x-551=0 equation:

4x^2+60x-551=0

a = 4; b = 60; c = -551;
Δ = b2-4ac
Δ = 602-4·4·(-551)
Δ = 12416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12416}=\sqrt{64*194}=\sqrt{64}*\sqrt{194}=8\sqrt{194}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-8\sqrt{194}}{2*4}=\frac{-60-8\sqrt{194}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+8\sqrt{194}}{2*4}=\frac{-60+8\sqrt{194}}{8}
$